Solve Quadratic Equation With Step-by-Step Math Problem Solver

Question: Consider The Following Function. F(x) = -2x2 + 16x - 22 (a) Use The Quadratic Formula To Find The Zeros Of F. (Enter Your Answers As A Comma-separated List. If An Answer Does Not Exist, Enter DNE.) (b) Find The Maximum Or Minimum Value Of F(x).The zeros of a function f are found by solving the equation f(x) = 0. Example 1 Find the zero of the linear function f is given by f(x) = -2 x + 4. Solution to Example 1 To find the zeros of function f, solve the equation f(x) = -2x + 4 = 0 Hence the zero of f is give by x = 2 Example 2 Find the zeros of the quadratic function f is given by f(xWhat are the zeros of the quadratic function f(x)=2×2+16x-9. Not b. What are the zeros of the quadratic function f(x)=6×2+12x-7. Not d. What are the zeros of the quadratic function f(x)=16×2+32x-9. B. Lie is solving a quadratic equation by completing the square. What should lie do next. B. Which is a zero of the quadratic function f(x)=9×23 • (x-5) Step-5 : Add up the four terms of step 4 : (x-3) • (x-5) Which is the desired factorization. Equation at the end of step 3 : 2 • (x - 3) • (x - 5) = 0 Step 4 : Theory - Roots of a product : 4.1 A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero.What are the zeros of the quadratic function f(x) = 2x2 + 16x - 9? Get the answers you need, now! ale01zamora ale01zamora 30.01.2020 Math Secondary School What are the zeros of the quadratic function f(x) = 2x2 + 16x - 9? 1 See answer ale01zamora is waiting for your help. Add your answer and earn points. Brainly User Brainly User Step-by

How to Find Zeros of a Function

Free quadratic equation calculator - Solve quadratic equations using factoring, complete the square and the quadratic formula step-by-step This website uses cookies to ensure you get the best experience.Given quadratic function is f(x) = 2x^{2} + 16x - 9 . We use the quadratic formula to find the zeros of the quadratic function f(x) = 2x^{2} + 16x - 9 . Comparing this with the quadratic function ax^{2} + bx + c = 0 , we get a = 2, b = 16, c = -9 Now putting these values of a, b, c on Quadratic formula we getFind the Roots (Zeros) f(x)=2x^2+16x-9. Set equal to . Solve for . Tap for more steps... Use the quadratic formula to find the solutions. Substitute the values , , and into the quadratic formula and solve for . Simplify. Tap for more steps... Simplify the numerator. Tap for more steps...The quadratic function f(x) = a(x - h) 2 + k, a not equal to zero, is said to be in standard form. If a is positive, the graph opens upward, and if a is negative, then it opens downward. The line of symmetry is the vertical line x = h, and the vertex is the point (h,k). Any quadratic function can be rewritten in standard form by completing the

Algebra Unit 3B Lesson 2 - Subjecto.com

Find the Maximum/Minimum Value f(x)=2x^2-16x-6. The maximum or minimum of a quadratic function occurs at . If is negative, the maximum value of the function is . If is positive, the minimum value of the function is . occurs at . Find the value of equal to . Substitute in the values of and .What is the vertex of the function f(x) = 2x2 + 16x + 21? Answer Save. 1 Answer. Relevance. Anonymous. 1 decade ago. Favorite Answer. Take derivative: 4x + 16. Set equal to zero and solve for x: 4x+16=0. 4x=-16. x= -16/4. x = -4. Plug -4 into original equation for x and solve to get y-coordinate: 2*16 + 16*-4 + 21. 32 - 64 + 21. y = -32 + 21Question: What are the zeros of the quadratic function f(x) = 2x2 + 16x - 9? x = -4 - and x = -4 + x = -4 - and x = -4 + x = -4 - and x = -4 + xStarlight tree farms sells douglas firs and noble first one December they sold 139 more douglas first than noble firs the total number of trees sold was 377 which equation could be used to solve for n the number of noble fir trees sold n-139=377 n+139=377 THIS ONE 2n-139=377 2n+139=377 suppose you are driving to visit a friend in another state you are driving 55 miles per hour you must drivef(x) = -x^2-6x f(x) = ax^2+bx+c f'(x) = 2ax+b f''(x) = 2a We are told that f(x) has a maximum value. :. f''(x) <0 -> a<0 We are also told that f(x) has zeros of -6 and 0 Hence: (x+6) is a factor of f(x) Also: -x is a factor of f(x) (since a<0) :. f(x) = -x(x+6) -> -x^2-6x To check our result, we are told that f_max = 9 With our result f'(x) = -2x-6 For a critical value f'(x) = 0 -> -2x-6 =0

(*9*):

What are the zeros of the quadratic function f(x) = 2x^2 + 16x - 9?

Zeros of a Function:

The zeros of a function are the issues where the graph of the function touches the x-axis. So which means that the zero of the function occurs at the x-axis or at y=0. So, fixing for the zeros, we just want to exchange y=Zero and resolve for x.

Answer and Explanation: 1

We are given the function eqf(x) = 2x^2 + 16x - 9 /eq.

Solving for the zeros, we've got:

Solution:

Substituting eqf(x)=0 /eq and solving for x, we have now:

$$\startalign\ 0&=2x^2+16x-9\ 2x^2+16x-9&=0\ x_1,\:2&=\frac-16\pm \sqrt16^2-4\cdot \:2\left(-9\right)2\cdot \:2\ x_1,\:2&=\frac-16\pm \:2\sqrt822\cdot \:2 \finishalign $$

Thus, we've got:

$$x_1=\frac-16+2\sqrt822\cdot \:2,\:x_2=\frac-16-2\sqrt822\cdot \:2\ x=\frac-8+\sqrt822,\:x=-\frac8+\sqrt822 $$

Therefore, the zeros of the given function are eq\boxed\colourbluex=\frac-8+\sqrt822,\:x=-\frac8+\sqrt822 /eq.

What are the zeros of the quadratic function f(x) = 2x2 ...

What are the zeros of the quadratic function f(x) = 2x2 ...

What are the zeros of the quadratic function f(x) = 2x2 ...

What are the zeros of the quadratic function f(x) = 2x2 ...

What are the zeros of the quadratic function f(x) = 2x2 ...

What are the zeros of the quadratic function f(x) = 2x2 ...

What are the zeros of the quadratic function f(x) = 2x2 ...

What are the zeros of the quadratic function f(x) = 2x2 ...